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CEDAR RAPIDS, Iowa — The No. 4/8 Endicott baseball team (45-8) is scheduled to play No. 25 Misericordia University (39-14) on day two of the NCAA Division III College World Series (CWS) on Saturday, June 3 at 11 AM (EST). Here's a preview of Saturday's elimination game matchup.
FIVE THINGS YOU NEED TO KNOW
- Saturday's contest will be the first-ever meeting between the two programs
- Common opponents for both teams include Baldwin Wallace (MU: W 15-9 | EC: L 13-9), MIT (MU: W 12-5 | EC: W 13-3 & 10-5), and Salve Regina (MU: L 11-4, W 12-9, W 19-6 | EC: W 11-3, W 4-1, W 8-7; L 5-2; W 1-0)
- Misericordia leads the country in hit-by-pitches with 155 total on the season; the Cougars were recently featured on foxsports.com for their record-breaking HBP numbers
- Misericordia fell to unanimous No. 1 Johns Hopkins, 10-5, on Friday despite witnessing the Blue Jays commit a CWS record-tying eight errors
- The Cougars entered the CWS ranked No. 35 in earned run average (4.25) and No. 40 in scoring (8.7)
TEAM INFO
Endicott: Roster | Stats | Schedule
Misericordia: Roster | Stats | Schedule
WHAT'S NEXT
The winner between No. 4/8 Endicott / No. 25 Misericordia (39-14) the loser of No. 1 Johns Hopkins / No. 10/12 Baldwin Wallace on Sunday, June 4 at 12 PM (EST).
The loser between the Gulls and Cougars will see their 2023 season come to a close.
For the latest on Endicott Athletics, follow the Gulls on social media on Facebook, Instagram, Twitter, and YouTube.
(Photo Credit - David Le '10)
